42x^2-50x^2+25x=0

Solution for 42x^2-50x^2+25x=0 equation:

42x^2-50x^2+25x=0

We add all the numbers together, and all the variables

-8x^2+25x=0

a = -8; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·(-8)·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*-8}=\frac{-50}{-16}
=3+1/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*-8}=\frac{0}{-16}
=0
$